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There is never a remainder when dividing by 1
When dividing by 2, even numbers have no remainders, odd numbers have a remainder of 1.
When dividing by 3, add up the digits in the number, then find the remainder of the sum when divided by 3. For example, find the remainder of 734762 ÷ 3. The sum of the digits is 7+3+4+7+6+2 = 29, and the remainder of 29 ÷ 3 is 2.
When finding the remainder of a big number divided by 4, drop off all but the last two digits and find the remainder for those last two digits. For example, the remainder of 2376452 ÷ 4 (think: drop off all but 52. The remainder of 52 ÷ 4 is 0.
Look only at the last digit of the number, and find the remainder of that digit ÷ 5.
Similar to remainders of 3 (above).Add up the digits in the number and find the remainder of the sum when divided by 9. That is your answer. For example, find the remainder of 737762 ÷ 9. The sum of the digits is 7+3+7+7+6+2 = 32, and the remainder of 32 ÷ 9 is 5.
Look only at the last digit of the number. That's the remainder!.
Here are some problems. See how quickly you can do them. If they don't fit the rule, put down an X for the answer. You can use the timer on the right to see how fast you are! (The timer will start when you press a key)
